JEE Main 2025 Jan 24 Shift 1, Chemistry Q14: Factors Affecting The Rate of a Chemical Reaction

JEE Main2025Jan 24, Shift 1Chemistry

For a reaction, $N_{2} O_{5} (g) \to 2N O_{2} (g) + \frac{1}{2} O_{2} (g)$ in a constant volume container, no products were present initially. The final pressure of the system when 50% of reaction gets completed is

A
$7/2$ times of initial pressure
B
$5$ times of initial pressure
C
$5/2$ times of initial pressure
D
$7/4$ times of initial pressure

Solution

Let the initial pressure of $N_{2} O_{5}$ be $P_{0}$ . After 50% reaction, the change in $N_{2} O_{5}$ partial pressure is $P_{0} /2$ .

Using the stoichiometric coefficients $1 : 2 : \frac{1}{2}$ , the partial pressures at this point are:

$P_{N_{2} O_{5}} = P_{0} - \frac{P _{0}}{2} = \frac{P _{0}}{2}$

$P_{N O_{2}} = 2 \times \frac{P _{0}}{2} = P_{0}$

$P_{O_{2}} = \frac{1}{2} \times \frac{P _{0}}{2} = \frac{P _{0}}{4}$

Total pressure: $P_{t o t} = \frac{P _{0}}{2} + P_{0} + \frac{P _{0}}{4} = \frac{7 P _{0}}{4}$

$∴$ Final pressure is $7/4$ times the initial. Option (4).

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JEE Main 2025 Jan 24 Shift 1, Chemistry Q14: Factors Affecting The Rate of a Chemical Reaction

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