JEE Main 2025 Jan 24 Shift 2, Chemistry Q10: Colour, Magnetism And Stability Of Co-ordination Compounds

JEE Main2025Jan 24, Shift 2Chemistry

Match List-I with List-II.

List-I (Transition metal ion)	List-II (Spin only magnetic moment (B.M.))
(A) $T i^{3 +}$	(I) 3.87
(B) $V^{2 +}$	(II) 0.00
(C) $N i^{2 +}$	(III) 1.73
(D) $S c^{3 +}$	(IV) 2.84

Choose the correct answer from the options given below :

Solution

The spin-only magnetic moment is $μ = n (n + 2) B.M.$ , where $n$ is the number of unpaired electrons.

Ion	Config.	$n$	$μ$ (B.M.)
$T i^{3 +}$	$3 d^{1}$	1	$3 \approx 1.73$ (III)
$V^{2 +}$	$3 d^{3}$	3	$15 \approx 3.87$ (I)
$N i^{2 +}$	$3 d^{8}$	2	$8 \approx 2.84$ (IV)
$S c^{3 +}$	$3 d^{0}$	0	$0.00$ (II)

Hence A-III, B-I, C-IV, D-II.

Correct option: (2)

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