JEE Main 2025 Jan 28 Shift 2, Physics Q23: Properties of Solids

JEE Main2025Jan 28, Shift 2Physics

The volume contraction of a solid copper cube of edge length 10 cm, when subjected to a hydraulic pressure of $7 \times 1 0^{6}$ Pa, would be _____ mm $^{3}$ .

(Given bulk modulus of copper $= 1.4 \times 1 0^{11}$ Nm $^{- 2}$ )

Your answer

Solution

Bulk modulus $B = - \frac{Δ P}{Δ V / V}$ , so the magnitude of contraction is

$∣Δ V ∣ = \frac{Δ P}{B} V$ .

With $V = (0.10 m)^{3} = 1 0^{- 3}$ m $^{3}$ :

$∣Δ V ∣ = \frac{7 \times 1 0 ^{6}}{1.4 \times 1 0 ^{11}} \times 1 0^{- 3} = 5 \times 1 0^{- 8} m^{3} = 50 mm^{3}$ .

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JEE Main 2025 Jan 28 Shift 2, Physics Q23: Properties of Solids

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