JEE Main 2025 Jan 28 Shift 2, Chemistry Q2: Periodicity In Atomic Properties

JEE Main2025Jan 28, Shift 2Chemistry

The amphoteric oxide among $V_{2} O_{3}$ , $V_{2} O_{4}$ and $V_{2} O_{5}$ upon reaction with alkali leads to formation of an oxide anion. The oxidation state of V in the oxide anion is :

A
$+ 3$
B
$+ 7$
C
$+ 5$
D
$+ 4$

Solution

Of the three oxides, $V_{2} O_{5}$ is amphoteric and reacts with alkali to give the vanadate ion:

$V_{2} O_{5} + 6 O H^{-} \to 2 V O_{4}^{3 -} + 3 H_{2} O$

In $V O_{4}^{3 -}$ , taking oxygen as $- 2$ and the overall charge as $- 3$ :

$x + 4 (- 2) = - 3 \Rightarrow x = + 5$ .

$∴$ vanadium is in the $+ 5$ oxidation state.

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JEE Main 2025 Jan 28 Shift 2, Chemistry Q2: Periodicity In Atomic Properties

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