JEE Main 2025 Jan 28 Shift 2, Chemistry Q13: Preparation of Alkyl Halides (Halo Alkanes) & Aryl Halides (Halo Arenes)
The major product of the following reaction is :

- A
6-Phenylhepta-2,4-diene
- B
2-Phenylhepta-2,5-diene
- C
6-Phenylhepta-3,5-diene
- D
2-Phenylhepta-2,4-diene

Excess alcoholic KOH on a vicinal/1,3-dibromide carries out two consecutive E2 eliminations, removing both Br atoms together with adjacent -hydrogens to generate a conjugated diene whenever possible (thermodynamic, Saytzeff product).
For the substrate shown, the two eliminations place the double bonds at the 2,3 and 4,5 positions of a 7-carbon chain, with the phenyl at C-2. Numbering the chain so that the phenyl-bearing alkene gets the lowest locant gives 2-phenylhepta-2,4-diene, a fully conjugated diene that also benefits from conjugation with the aromatic ring.
Concept behind this question
Preparation of Alkyl Halides (Halo Alkanes) & Aryl Halides (Halo Arenes)Notes, formulas and examples →More previous year questions on Preparation of Alkyl Halides (Halo Alkanes) & Aryl Halides (Halo Arenes)
Practice more Chemistry
Concept-wise practice with instant solutions on Fundamenthol.
Start practicing →