JEE Main 2025 Jan 29 Shift 1, Physics Q22: Kinetic Theory of an Ideal Gases

JEE Main2025Jan 29, Shift 1Physics

A container of fixed volume contains a gas at $2 7^{\circ} C .$ To double the pressure of the gas, the temperature of gas should be raised to ______ $^{\circ} C .$

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Solution

At constant volume, $\frac{P}{T} = const$ (Gay-Lussac's law).

Initial: $P_{1} = P$ , $T_{1} = 27 + 273 = 300 K .$ Final: $P_{2} = 2 P .$

$\frac{P}{300} = \frac{2 P}{T _{2}} \Rightarrow T_{2} = 600 K .$

Converting back: $T_{2} = 600 - 273 = 32 7^{\circ} C .$

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JEE Main 2025 Jan 29 Shift 1, Physics Q22: Kinetic Theory of an Ideal Gases

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