JEE Main 2026 — Apr 2, Shift 1 — Chemistry solution

JEE Main2026Apr 2, Shift 1Chemistry

Match List-I with List-II.

List-I Mixture of Compounds	List-II Reagent used to distinguish
A. Diethyl amine + Ethyl amine	I. Bromine water
B. Acetaldehyde + Acetone	II. $C H C l_{3} + K O H, Δ$
C. Ethanol + Phenol	III. Neutral $F e C l_{3}$
D. Benzoic acid + Cinnamic acid	IV. Ammonical silver nitrate

Choose the correct answer from the options given below :

A
A-IV, B-II, C-I, D-III
B
A-IV, B-II, C-III, D-I
C
A-II, B-IV, C-I, D-III
D
A-II, B-IV, C-III, D-I

Solution

Pairing each mixture with the test reagent that gives a difference:

A. Diethyl amine (2 $^{\circ}$ ) vs ethyl amine (1 $^{\circ}$ ): the carbylamine test ( $C H C l_{3} + K O H, Δ$ ) is positive only for primary amines, giving a foul-smelling isocyanide. Match II.

B. Acetaldehyde vs acetone: Tollens' reagent (ammoniacal $A g N O_{3}$ ) gives a silver mirror only with the aldehyde. Match IV.

C. Ethanol vs phenol: phenol gives a violet colour with neutral $F e C l_{3}$ ; ethanol does not. Match III.

D. Benzoic vs cinnamic acid: cinnamic acid has a $C = C$ double bond that decolourises bromine water; benzoic acid does not. Match I.

Hence A-II, B-IV, C-III, D-I.

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