JEE Main 2026 — Apr 4, Shift 2 — Physics solution

JEE Main2026Apr 4, Shift 2Physics

A water spray gun is attached to a hose of cross sectional area 30 cm $^{2}$ . The gun comprises of 10 perforations each of cross sectional area of 15 mm $^{2}$ . If the water flows in the hose with the speed of 50 cm/s, calculate the speed at which the water flows out from each perforation. (Neglect any edge effects)

A
100 m/s
B
10 m/s
C
1000 m/s
D
$15 \times 1 0^{2}$ m/s

Solution

By continuity, the volume flow rate through the hose equals the total volume flow rate through all perforations:

$A V = 10 a v$ .

With $A = 30 cm^{2}$ , $a = 15 mm^{2} = 0.15 cm^{2}$ , $V = 50 cm/s$ :

$v = \frac{A V}{10 a} = \frac{30 \times 50}{10 \times 0.15} = 1000 cm/s = 10 m/s$ .

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