JEE Main 2026 Apr 5 Shift 1, Physics Q23: Types and Equations of Waves

JEE Main2026Apr 5, Shift 1Physics

A transverse wave on a string is described by $y = 3 sin (36 t + 0.018 x + π /4)$ . Where $x$ , $y$ are in cm and $t$ in seconds. The least distance between the two successive crests in the wave is _____ cm. (Nearest integer) ( $π = 3.14$ )

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Solution

The least distance between successive crests is one full wavelength $λ = \frac{2 π}{k}$ .

From the wave equation, $k = 0.018$ cm $^{- 1}$ , so $λ = \frac{2 π}{0.018} = \frac{2 \times 3.14}{0.018} \approx 348.89$ cm.

Rounded to the nearest integer: $349$ cm.

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JEE Main 2026 Apr 5 Shift 1, Physics Q23: Types and Equations of Waves

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