JEE Main 2026 Apr 5 Shift 1, Chemistry Q2: Quantum Numbers

JEE Main2026Apr 5, Shift 1Chemistry

Arrange the following atomic orbitals of multi electron atoms in order of increasing energy.

(A) $n = 3, ℓ = 2, m = + 1$ (B) $n = 4, ℓ = 0, m = 0$

(E) $n = 2, ℓ = 1, m = + 1$

Choose the correct answer from the options given below :

Solution

Apply the $(n + ℓ)$ rule: lower $(n + ℓ)$ means lower energy, and for equal values the orbital with smaller $n$ comes first.

(A) $3 d$ : $n + ℓ = 5$ . (B) $4 s$ : $n + ℓ = 4$ . (C) $6 p$ : $n + ℓ = 7$ . (D) $5 p$ : $n + ℓ = 6$ . (E) $2 p$ : $n + ℓ = 3$ .

Ordering by $(n + ℓ)$ : $E (3) < B (4) < A (5) < D (6) < C (7)$ .

Concept behind this question

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