JEE Main 2026 — Apr 5, Shift 1 — Chemistry solution

JEE Main2026Apr 5, Shift 1Chemistry

Arrange the following resultant mixtures in increasing order of their pH values :

A. 10 mL 0.2 M Ca(OH) $_{2}$ + 25 mL 0.1 M HCl

B. 10 mL 0.01 M H $_{2}$ SO $_{4}$ + 10 mL 0.01 M Ca(OH) $_{2}$

C. 10 mL 0.1 M H $_{2}$ SO $_{4}$ + 10 mL 0.1 M KOH

Choose the correct answer from the options given below :

A
B < C < A
B
C < A < B
C
C < B < A
D
A < C < B

Solution

Compute millimoles of $H^{+}$ and $OH^{-}$ in each mixture.

A: $OH^{-} = 10 \times 0.2 \times 2 = 4$ mmol; $H^{+} = 25 \times 0.1 = 2.5$ mmol. Excess $OH^{-} = 1.5$ mmol, so solution is basic ( $pH > 7$ ).

B: $H^{+} = 10 \times 0.01 \times 2 = 0.2$ mmol; $OH^{-} = 10 \times 0.01 \times 2 = 0.2$ mmol. Complete neutralization with a salt of strong acid and strong base, so $pH = 7$ .

C: $H^{+} = 10 \times 0.1 \times 2 = 2$ mmol; $OH^{-} = 10 \times 0.1 = 1$ mmol. Excess $H^{+} = 1$ mmol, so solution is acidic ( $pH < 7$ ).

Ordering: $C < B < A$ .

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