JEE Main 2026 Apr 5 Shift 2, Physics Q2: Measurements

JEE Main2026Apr 5, Shift 2Physics

In an experiment to determine the resistance of a given wire using Ohm's law, the voltmeter and ammeter readings are noted as 10V and 5 A, respectively. The least counts of voltmeter and ammeter are 500 mV and 200 mA, respectively. The estimated error in the resistance measurement is _________ $Ω$ .

A
0.25
B
2
C
2.5
D
0.18

Solution

From Ohm's law, $R = V / I = 10/5 = 2 Ω$ .

Relative error: $\frac{Δ R}{R} = \frac{Δ V}{V} + \frac{Δ I}{I} = \frac{0.5}{10} + \frac{0.2}{5} = 0.05 + 0.04 = 0.09$ .

$∴ Δ R = 0.09 \times 2 = 0.18 Ω$ .

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JEE Main 2026 Apr 5 Shift 2, Physics Q2: Measurements

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