Fundamentholfundamenthol

JEE Main 2026 Apr 5 Shift 2, Physics Q4: Motion In One Dimension

JEE Main2026Apr 5, Shift 2Physics
Q.

The velocity () versus time () plot of a particle is shown in the figure, for a time interval of 40 s. The total distance travelled by the particle and the average velocity during this period are, respectively _____.

  1. A

    25 m and zero

  2. B

    50 m and zero

  3. C

    100 m and zero

  4. D

    100 m and 2.5 m/s

Solution

Distance = total area under the speed-time curve (taking magnitudes of both triangles):

m.

The positive and negative areas of the velocity-time graph are equal, so net displacement is zero.

Average velocity m/s.

Concept behind this question

Motion In One DimensionNotes, formulas and examples →

More previous year questions on Motion In One Dimension

Practice more Physics

Concept-wise practice with instant solutions on Fundamenthol.

Start practicing →