JEE Main 2026 Apr 5 Shift 2, Physics Q19: Mass-Energy and Nuclear Binding Energy

JEE Main2026Apr 5, Shift 2Physics

Assuming the experimental mass of $_{6}^{12} C$ as 12u, the mass defect of $_{6}^{12} C$ atom is _____ MeV/c $^{2}$ . (Mass of proton = 1.00727 u, mass of neutron = 1.00866 u, 1 u = 931.5 MeV/c $^{2}$ and $c$ is the speed of light in vacuum.)

A
127.5
B
89.03
C
272.0
D
92.0

Solution

Carbon-12 has 6 protons and 6 neutrons.

$Δ m = 6 m_{p} + 6 m_{n} - m_{C} = 6 (1.00727 + 1.00866) - 12$

$= 6 \times 2.01593 - 12 = 12.09558 - 12 = 0.09558$ u.

Converting: $0.09558 \times 931.5 \approx 89.03$ MeV/c $^{2}$ .

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JEE Main 2026 Apr 5 Shift 2, Physics Q19: Mass-Energy and Nuclear Binding Energy

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