JEE Main 2026 Apr 6 Shift 1, Physics Q9: Properties of Solids

JEE Main2026Apr 6, Shift 1Physics

The two wires A and B of equal cross-section but of different materials are joined together. The ratio of Young's modulus of wire A and wire B is $20/11$ . When the joined wire is kept under certain tension the elongations in the wires A and B are equal. If the length of wire A is $2.2$ m, then the length of wire B is____m.

A
$1.1$
B
$2.22$
C
$1.21$
D
$4.44$

Solution

From $Δ l = \frac{T L}{Y A}$ : equal tension $T$ , equal cross-section $A$ , equal elongation $Δ l$ implies $\frac{L _{A}}{Y _{A}} = \frac{L _{B}}{Y _{B}}$ , i.e. $L \propto Y$ .

$\frac{L _{B}}{L _{A}} = \frac{Y _{B}}{Y _{A}} = \frac{11}{20}$ .

$L_{B} = \frac{11}{20} \times 2.2 = 1.21$ m.

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JEE Main 2026 Apr 6 Shift 1, Physics Q9: Properties of Solids

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