JEE Main 2026 Apr 6 Shift 2, Physics Q14: Faraday’s Law of Induction

JEE Main2026Apr 6, Shift 2Physics

A square loop of side 2 cm is placed in a time varying magnetic field with magnitude as $B = 0.4 sin (300 t)$ Tesla. The normal to the plane of loop makes an angle of $6 0^{\circ}$ with the field. The maximum induced emf produced in the loop is ____ mV.

A
12
B
18
C
21
D
24

Solution

Flux: $ϕ = B A cos θ = 0.4 sin (300 t) \cdot A cos 6 0^{\circ}$ .

Area $A = (0.02)^{2} = 4 \times 1 0^{- 4}$ m $^{2}$ .

Induced emf: $ε = - \frac{d ϕ}{d t} = - 0.4 \times 300 \times A cos 6 0^{\circ} cos (300 t)$ .

Maximum magnitude: $∣ ε ∣_{ma x} = 0.4 \times 300 \times 4 \times 1 0^{- 4} \times \frac{1}{2} = 0.024$ V $= 24$ mV.

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JEE Main 2026 Apr 6 Shift 2, Physics Q14: Faraday’s Law of Induction

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