JEE Main 2026 Apr 6 Shift 2, Physics Q17: Prism

JEE Main2026Apr 6, Shift 2Physics

Angle of minimum deviation is equal to the half of the angle of prism in an equilateral prism. The refractive index of the prism is ______.

Solution

For an equilateral prism $A = 6 0^{\circ}$ ; given $δ_{min} = A /2 = 3 0^{\circ}$ .

Prism formula: $μ = \frac{sin ( \frac{A + δ _{min}}{2} )}{sin ( \frac{A}{2} )} = \frac{sin 4 5 ^{\circ}}{sin 3 0 ^{\circ}} = \frac{1/ 2}{1/2} = 2$ .

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