JEE Main 2026 — Jan 21, Shift 1 — Physics solution

JEE Main2026Jan 21, Shift 1Physics

Potential energy (V) versus distance (x) is given by the graph, Rank various regions as per the magnitudes of the force (F) acting on a particle from high to low.

A
$F_{B C} > F_{C D} > F_{D E} > F_{A B}$
B
$F_{C D} > F_{A B} > F_{B C} > F_{D E}$
C
$F_{C D} > F_{D E} > F_{A B} > F_{B C}$
D
$F_{B C} > F_{A B} > F_{D E} > F_{C D}$

Solution

Force from a potential: $F = - \frac{d V}{d x}$ , so $∣ F ∣$ equals the magnitude of the slope of $V$ versus $x$ in each region.

Reading the slopes off the graph: $∣ s_{B C} ∣ \approx 2$ (steepest rise), $∣ s_{A B} ∣ = 1$ , $∣ s_{D E} ∣ \approx 2/3$ (gradual descent), $∣ s_{C D} ∣ = 0$ (flat).

Ordering by magnitude: $F_{B C} > F_{A B} > F_{D E} > F_{C D}$ .

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