JEE Main 2026 — Jan 21, Shift 1 — Chemistry solution

JEE Main2026Jan 21, Shift 1Chemistry

Consider the following reactions:

$N a C l + K_{2} C r_{2} O_{7} + H_{2} S O_{4} \to A + K H S O_{4} + N a H S O_{4} + H_{2} O$

$A + N a O H \to B + N a C l + H_{2} O$

$B + H_{2} S O_{4} + H_{2} O_{2} \to C + N a_{2} S O_{4} + H_{2} O$

In the product 'C', 'X' is the number of $O_{2}^{2 -}$ units, 'Y' is the total number of oxygen atoms present, and 'Z' is the oxidation state of Cr. The value of $X + Y + Z$ is ________.

Your answer

Solution

$A = C r O_{2} C l_{2}$ (chromyl chloride), $B = N a_{2} C r O_{4}$ , $C = C r O_{5}$ (chromium peroxide).

In $C r O_{5}$ : Cr is in +6 oxidation state, with 2 peroxide ( $O_{2}^{2 -}$ ) units and one $= O$ , total 5 O atoms.

$X = 2$ , $Y = 5$ , $Z = 6 \Rightarrow X + Y + Z = 13$ .

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