JEE Main 2026 — Jan 21, Shift 2 — Physics solution

JEE Main2026Jan 21, Shift 2Physics

The kinetic energy of a simple harmonic oscillator is oscillating with angular frequency of 176 rad/s. The frequency of this simple harmonic oscillator is_____Hz. $[take π = \frac{22}{7}]$

A
14
B
88
C
28
D
176

Solution

For SHM with displacement angular frequency $ω$ , the kinetic energy oscillates at twice that rate. So the KE's angular frequency is $ω_{K E} = 2 ω = 176$ rad/s, giving $ω = 88$ rad/s for the oscillator itself.

Frequency: $f = \frac{ω}{2 π} = \frac{88}{2 \times 22/7} = \frac{88 \times 7}{44} = 14$ Hz.

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