JEE Main 2026 — Jan 22, Shift 1 — Chemistry solution

JEE Main2026Jan 22, Shift 1Chemistry

Match the LIST-I with LIST-II

Choose the correct answer from the option given below:

Solution

Compute each magnitude.

A. $W = - n R T ln (V_{2} / V_{1}) = - 2 \times 8.314 \times 300 \times ln 10/1000 \approx - 11.5$ kJ ⇒ magnitude 11.5 (II).

B. $W = - P_{e x t} (V_{2} - V_{1}) = - 3 kPa \times (3 - 1) m^{3} = - 6$ kJ ⇒ magnitude 6 (III).

C. $Δ U = n C_{V} Δ T = 1 \times \frac{3}{2} \times 8.314 \times 320/1000 \approx 3.99$ kJ ⇒ magnitude 4 (I).

D. $Δ H = n C_{P} Δ T = 1 \times \frac{5}{2} \times 8.314 \times 337/1000 \approx 7$ kJ ⇒ magnitude 7 (IV).

So A-II, B-III, C-I, D-IV.

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