JEE Main 2026 Jan 22 Shift 2, Chemistry Q24: Preparation of Amines

JEE Main2026Jan 22, Shift 2Chemistry

The mass of benzanilide obtained from the benzoylation reaction of 5.8 g of aniline, if yield of product is 82%, is ______ g (nearest integer).

(Given molar mass in g mol $^{- 1}$ H:1, C:12, N:14, O:16)

Your answer

Solution

Aniline ( $C_{6} H_{5} N H_{2}$ , M = 93) reacts with benzoyl chloride to give benzanilide ( $C_{6} H_{5} N H C O C_{6} H_{5}$ , M = 197). Reaction is 1 : 1.

Moles of aniline $= \frac{5.8}{93} \approx 0.0624$ mol.

Theoretical moles of benzanilide $= 0.0624$ . With 82% yield: $0.0624 \times 0.82 \approx 0.0512$ mol.

Mass $= 0.0512 \times 197 \approx 10.08$ g, rounded to 10 g.

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JEE Main 2026 Jan 22 Shift 2, Chemistry Q24: Preparation of Amines

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