JEE Main 2026 Jan 23 Shift 2, Physics Q3: Newton's Laws Of Motion

JEE Main2026Jan 23, Shift 2Physics

A block is sliding down on an inclined plane of slope $θ$ and at an instant $t = 0$ this block is given an upward momentum so that it starts moving up on the inclined surface with velocity $u$ . The distance ( $S$ ) travelled by the block before its velocity become zero, is ______.

(g = gravitational acceleration)

A
$\frac{u ^{2}}{4 g sin θ}$
B
$\frac{2 u ^{2}}{g cos θ}$
C
$\frac{u ^{2}}{2 g cos θ}$
D
$\frac{u ^{2}}{2 g sin θ}$

Solution

The block moves up the incline; component of gravity along the incline (down the slope) is $g sin θ$ . With no friction stated, deceleration $a = g sin θ$ .

Using $v^{2} = u^{2} - 2 a S$ with final $v = 0$ :

$S = \frac{u ^{2}}{2 g sin θ}$ .

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JEE Main 2026 Jan 23 Shift 2, Physics Q3: Newton's Laws Of Motion

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