JEE Main 2026 — Jan 23, Shift 2 — Physics solution

JEE Main2026Jan 23, Shift 2Physics

When an unpolarized light falls at a particular angle on a glass plate (placed in air), it is observed that the reflected beam is linearly polarized. The angle of refracted beam with respect to the normal is ______.

( $tan^{- 1} (1.52) = 57. 7^{\circ}$ , refractive indices of air and glass are $1.00$ and $1.52$ , respectively)

A
$39. 6^{\circ}$
B
$32. 3^{\circ}$
C
$42. 6^{\circ}$
D
$36. 3^{\circ}$

Solution

Reflected beam fully polarized ⇒ incidence is at Brewster's angle.

$tan i_{B} = \frac{μ _{g l a ss}}{μ _{ai r}} = 1.52 \Rightarrow i_{B} = 57. 7^{\circ}$ .

At Brewster incidence, the reflected and refracted rays are perpendicular, so $i_{B} + r = 9 0^{\circ}$ .

$r = 9 0^{\circ} - 57. 7^{\circ} = 32. 3^{\circ}$ .

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