JEE Main 2026 — Jan 23, Shift 2 — Chemistry solution

JEE Main2026Jan 23, Shift 2Chemistry

Given above is the concentration vs time plot for a dissociation reaction : $A \to n B$ .

Based on the data of the initial phase of the reaction (initial 10 min), the value of n is ________.

Solution

From the graph, during the first 10 minutes:

Drop in $[A]$ : $0.05 - 0.04 = 0.01$ M

Rise in $[B]$ : $0.03 - 0 = 0.03$ M

Stoichiometry of $A \to n B$ requires $Δ [B] = n \cdot Δ [A]$ , so:

$n = \frac{0.03}{0.01} = 3$

$∴ n = 3$ .

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