JEE Main 2026 — Jan 28, Shift 2 — Physics solution

JEE Main2026Jan 28, Shift 2Physics

A nucleus has mass number $α$ and radius $R_{α}$ . Another nucleus has mass number $β$ and radius $R_{β}$ . If $β = 8 α$ then $R_{α} / R_{β}$ is :

Solution

Nuclear radius scales as $R = R_{0} A^{1/3}$ where $A$ is mass number.

$\frac{R _{α}}{R _{β}} = (\frac{α}{β})^{1/3} = (\frac{1}{8})^{1/3} = \frac{1}{2} = 0.5$ .

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