JEE Main 2026 — Jan 28, Shift 2 — Chemistry solution

JEE Main2026Jan 28, Shift 2Chemistry

A student has been given 0.314 g of an organic compound and asked to estimate Sulphur. During the experiment, the student has obtained 0.4813 g of barium sulphate. The percentage of sulphur present in the compound is ____ . (Given Molar mass in g mol $^{- 1}$ S:32, BaSO $_{4}$ :233)

A
42.10%
B
63.15%
C
21.05%
D
48.24%

Solution

In Carius/gravimetric estimation, all sulphur in the organic compound is converted to BaSO $_{4}$ . Mass fraction of S in BaSO $_{4} = \frac{32}{233}$ .

$% S = \frac{32}{233} \times \frac{mass of BaSO _{4}}{mass of sample} \times 100 = \frac{32}{233} \times \frac{0.4813}{0.314} \times 100 \approx 21.05%$ .

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