Properties of Alcohol
PHYSICAL PROPERTIES
Solubility
Alcohols are soluble in water due to formation of H – bonding between water & them. As the molecular mass increases, the alkyl group become larger which resists the formation of
H – bonds with water molecules and hence the solubility goes an decreasing.
Boiling Point
Intermolecular H – bonding is present between alcohol molecules. This makes high boiling point.
Amongst the isomeric alcohols, the order of boiling point is 1º > 2º > 3º alcohol.
CHEMICAL PROPERTIES
Chemical properties of alcohols can be discussed under following categories:
(A) Reaction involving breaking of carbon – oxygen bond.
(B) Reaction involving breaking of oxygen – hydrogen bond.
(C) Oxidation of alcohols.
(D) Dehydrogenation of alcohols.
(E) Some miscellaneous reactions of monohydric alcohol.
(A) Reaction involving breaking of carbon – oxygen bond
Order of reactivity of alcohol. 3º > 2º > 1º
(i) SN reaction
(ii) Dehydration of alcohol
ꃞhydration of alcohol to give alkene.
(a) ꃞhydrating agents are
onc H2SO4/, KHSO4/, H3PO4/, Anhyd Al2O3/, Anhyd PCl5/, Anhyd ZnCl2/, BF3/, P2O5/.
(b) Reactivity of alcohols. (Ease of dehydration)
ਃº > 2º > 1º
(c) Product formation always takes place by saytzeff rule.
Alcohols on acetylation gives acetyl derivative which on pyrolytic elimination always gives Hofmann product.
Mechanism in presence of acidic medium
E1 mechanism: follow saytzeff’s rule.
(B) Reactions due to breaking of oxygen hydrogen bond. (Reactions due to acidic character of alcohols)
(a) ਊlcohols are acidic in nature because hydrogen is present on electro negative oxygen atom.
(b) ਊlcohol is weaker acid
acidity stability of acid anions.
ꂬidity of 1º > 2º > 3º
ਊlcohols give following reactions due to breaking of oxygen – hydrogen bond.
(i) Reaction with metal
M = 1st group metal.
M = Al, Mg, Zn
ਊluminium alkoxide
(ii) Esterification (With carboxylic acid)
It is reversible acid catalysed reaction. It follow SN1 mechanism.
Increasing the size of alkyl group on alcohol part decreases the nucleophilic character because steric hindrance increases.
.
Order of reactivity of alcohols CH3OH > 1º alc > 2º alc > 3º alc
(iii) Ester formation with proton acid having –OH group: to give inorganic ester
(iv) Alkylation of Alcohol
R-O-H\xrightarrow[\begin{smallmatrix} or \\#xA0C{{H}_{3}}I/{{K}_{2}}C{{O}_{3}} \end{smallmatrix}]{{{\left( C{{H}_{3}} \right)}_{2}}S{{O}_{4}}/NaOH}R-O-C{{H}_{3}}
Methylation is mainly used for determination of hydroxyl groups in an unknown compound.
(C) Oxidation of alcohol
Oxidation of alcohol is dehydrogenation reaction which is 1, 2 – elimination reaction.
So oxidation of alcohol numbers of - hydrogen atom.
(a) With mild oxidising agents:
Like
(i) X2
(ii) Fenton reagent [FeSO4/H2O2]
(iii) Jones reagent / CHCOCH3 [CrO3/dil. BaSO4]
(iv) K2Cr2O7/H+ cold
Note:
PCC (Pyridinium chloro chromate) is a selective reagent which converts 1º alc to aldehyde.
(b) With strong oxidising agent
Oxidising agents are
(i) (ii)
(iii) (iv)
(D) Dehydrogenation with Cu/573K or Ag/573K
(a)ਁº alcohol aldehyde
(b) ਂº alcohol ketone
(c) ਃº alc undergo dehydration to form alkene.
Reduction
(E) Miscellaneous reactions of mono hydric alcohol
(i) Methylation with CH2N2 in presence of BF3.
(ii) Haloform reaction
thyl alcohol and 2º methyl alcohol gives haloform reaction.
Distinguishing 1º, 2º, 3º alcohol
PERIODATE OXIDATION
Compounds that have hydroxyl group on adjacent atoms undergo oxidation cleavage when they are treated with aq. Periodic acid (HIO4). The reaction breaks carbon carbon bonds and produced carbonyl compounds (aldehyde, ketones or acids)
It takes place through a cyclic intermediate.
Other examples
This oxidation is useful in determination of structure.
Illustration 1. Write the products of the reaction of t-butyl alcohol with PBr3, conc. H2SO4, CH3COCl, Na, CH3MgBr, Na2Cr2O7/H2SO4.
Solution: .
PINACOL – PINACOLONE REARRANGEMENT
Action of H2SO4 on 1, 2 diols.
Ditertiory – 1, 2 diols convert in to ketones on treatment wit H2SO4.
Mechanism
Migratory preference of the group
Migration depends on the stability of Transition state.
In general migration of C6H5 > alkyl
Illustration 2. List three methods with chemical equations for the preparation of alcohols from alkenes.
Solution: Hydration, hydroboration and oxymercuration – demercuration of alkenes.
Hydration:
Hydroboration
Oxymercuration – demercuration
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