JEE Advanced 2023 Paper 2, Chemistry Section 3 Q2: Valence Bond Theory And Hybridisation

JEE Advanced2023Paper 2Chemistry Section 3

Among $[I_{3}]^{+}$ , $[S i O_{4}]^{4 -}$ , $S O_{2} C l_{2}$ , $X e F_{2}$ , $S F_{4}$ , $C l F_{3}$ , $N i (C O)_{4}$ , $X e O_{2} F_{2}$ , $[P tC l_{4}]^{2 -}$ , $X e F_{4}$ , and $S O C l_{2}$ , the total number of species having $s p^{3}$ hybridised central atom is ______.

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Solution

Apply VSEPR (steric number = bonded atoms + lone pairs on central atom) to each species.

$s p^{3}$ (steric number 4):

$[I_{3}]^{+}$ : central I has 2 bonds + 2 lone pairs $\Rightarrow s p^{3}$ .

$[S i O_{4}]^{4 -}$ : Si has 4 bonds, no lone pair, tetrahedral $\Rightarrow s p^{3}$ .

$S O_{2} C l_{2}$ : S has 4 bonds, no lone pair $\Rightarrow s p^{3}$ .

$N i (C O)_{4}$ : tetrahedral $N i (0)$ $\Rightarrow s p^{3}$ .

$S O C l_{2}$ : S has 3 bonds + 1 lone pair $\Rightarrow s p^{3}$ .

Other hybridisations (not counted):

$X e F_{2}$ , $S F_{4}$ , $C l F_{3}$ , $X e O_{2} F_{2}$ : each $s p^{3} d$ .

$X e F_{4}$ : $s p^{3} d^{2}$ .

$[P tC l_{4}]^{2 -}$ : square planar $P t (I I)$ , $d s p^{2}$ .

Therefore the number of species with $s p^{3}$ central atom is $5$ .

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JEE Advanced 2023 Paper 2, Chemistry Section 3 Q2: Valence Bond Theory And Hybridisation

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