JEE Advanced 2025 — Paper 2 — CHEM-I solution

JEE Advanced2025Paper 2CHEM-I

The complete hydrolysis of ICl, ClF $_{3}$ and BrF $_{5}$ , respectively, gives

A
IO $^{-}$ , ClO $_{2}^{-}$ and BrO $_{3}^{-}$
B
IO $_{3}^{-}$ , ClO $_{2}^{-}$ and BrO $_{3}^{-}$
C
IO $^{-}$ , ClO $^{-}$ and BrO $_{2}^{-}$
D
IO $_{3}^{-}$ , ClO $_{4}^{-}$ and BrO $_{2}^{-}$

Solution

Interhalogens hydrolyse such that the less electronegative central halogen ends up bonded to oxygen in an oxoacid, whose conjugate base form is given by the question. The oxidation state of the central halogen in the starting interhalogen is preserved (loosely: number of $F$ / $C l$ on the central atom equals the number of $O$ -bonds in the product oxoanion).

ICl (I in +1): ICl + H $_{2}$ O $\to$ HIO + HCl, conjugate base IO $^{-}$ (hypoiodite).

ClF $_{3}$ (Cl in +3): ClF $_{3}$ + 2H $_{2}$ O $\to$ HClO $_{2}$ + 3HF, conjugate base ClO $_{2}^{-}$ (chlorite).

BrF $_{5}$ (Br in +5): BrF $_{5}$ + 3H $_{2}$ O $\to$ HBrO $_{3}$ + 5HF, conjugate base BrO $_{3}^{-}$ (bromate).

$∴$ Option (A) is correct.

← Back to full paper

Practice more CHEM-I

Concept-wise practice with instant solutions on Fundamenthol.

Start practicing →