JEE Advanced 2025 — Paper 2 — CHEM-I solution

JEE Advanced2025Paper 2CHEM-I

During sodium nitroprusside test of sulphide ion in an aqueous solution, one of the ligands coordinated to the metal ion is converted to

A
NOS $^{-}$
B
SCN $^{-}$
C
SNO $^{-}$
D
NCS $^{-}$

Solution

Sodium nitroprusside is Na $_{2}$ [Fe(CN) $_{5}$ (NO)]. In the test, sulphide ion attacks the nitrosyl (NO) ligand coordinated to iron, converting it into the thionitrosyl-type ligand NOS $^{-}$ , and producing the characteristic purple solution:

Na $_{2}$ [Fe(CN) $_{5}$ (NO)] + Na $_{2}$ S $\to$ Na $_{4}$ [Fe(CN) $_{5}$ (NOS)] (purple)

$∴$ Option (A) is correct.

← Back to full paper

Practice more CHEM-I

Concept-wise practice with instant solutions on Fundamenthol.

Start practicing →