JEE Main 2025 Apr 2 Shift 1, Chemistry Q8: Stoichiometry

JEE Main2025Apr 2, Shift 1Chemistry

$C a C O_{3} (s) + 2 H C l (a q) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)$

Consider the above reaction, what mass of $C a C l_{2}$ will be formed if 250 mL of 0.76 M HCl reacts with 1000 g of $C a C O_{3}$ ?

(Given : Molar mass of Ca, C, O, H and Cl are 40, 12, 16, 1 and 35.5 g $m o l^{- 1}$ , respectively)

Solution

Compute the moles of each reactant.

$n (C a C O_{3}) = \frac{1000}{100} = 10$ mol.

$n (H C l) = 0.76 \times \frac{250}{1000} = 0.19$ mol.

The reaction consumes 2 mol HCl per mol $C a C O_{3}$ . With only 0.19 mol HCl available against 10 mol carbonate, HCl is the limiting reagent.

$n (C a C l_{2}) = \frac{n ( H C l )}{2} = \frac{0.19}{2} = 0.095 mol$

Molar mass of $C a C l_{2} = 40 + 2 (35.5) = 111$ g/mol.

$Mass = 0.095 \times 111 = 10.545 g$

$∴$ Option (3) is correct.

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