JEE Main 2025 Apr 2 Shift 1, Chemistry Q10: Valence Bond Theory And Hybridisation

JEE Main2025Apr 2, Shift 1Chemistry

Among $S O_{2}$ , $N F_{3}$ , $N H_{3}$ , $X e F_{2}$ , $C l F_{3}$ and $S F_{4}$ , the hybridization of the molecule with non-zero dipole moment and highest number of lone-pairs of electrons on the central atom is

A
$s p^{3}$
B
$d s p^{2}$
C
$s p^{3} d^{2}$
D
$s p^{3} d$

Solution

Summarising hybridization, dipole moment and lone-pair count on the central atom:

Molecule	Hybridisation	Dipole moment	Lone pairs on central atom
$S O_{2}$	$s p^{2}$	Non-zero	1
$N F_{3}$	$s p^{3}$	Non-zero	1
$N H_{3}$	$s p^{3}$	Non-zero	1
$X e F_{2}$	$s p^{3} d$	Zero	3
$C l F_{3}$	$s p^{3} d$	Non-zero	2
$S F_{4}$	$s p^{3} d$	Non-zero	1

The filter is: non-zero dipole (eliminates $X e F_{2}$ ) AND maximum lone pairs. Among the remaining species, $C l F_{3}$ has 2 lone pairs, the highest count, with $s p^{3} d$ hybridisation.

$∴$ Option (4) is correct.

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JEE Main 2025 Apr 2 Shift 1, Chemistry Q10: Valence Bond Theory And Hybridisation

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