JEE Main 2025 Apr 2 Shift 1, Chemistry Q23: Mole Concept And Equivalent Concept

JEE Main2025Apr 2, Shift 1Chemistry

0.1 mol of the following given antiviral compound (P) will weigh _______ $\times 1 0^{- 1}$ g

(Given : molar mass in g $m o l^{- 1}$ H: 1, C : 12, N : 14, O : 16, F : 19, I : 127)

Your answer

Solution

Count each atom in compound (P) from its structure:

Pyrimidine-2,4-dione (uracil-like) base with –I at C5: 4 C, 2 N, 2 O, 1 H (N–H) plus 1 I, with 1 H remaining on C6.

Sugar (modified ribose, deoxy-fluoro): a 5-membered oxolane ring + an exocyclic –CH2OH. Atoms contributed: 5 C, 3 O (ring O + two –OH), 1 F, and the hydrogens on the ring carbons and hydroxyls.

Tallying the entire molecule gives the molecular formula $C_{9} H_{10} F I N_{2} O_{5}$ .

Molar mass calculation:

$M = 9 (12) + 10 (1) + 1 (19) + 1 (127) + 2 (14) + 5 (16)$

$M = 108 + 10 + 19 + 127 + 28 + 80 = 372 g/mol$

Mass of 0.1 mol $= 0.1 \times 372 = 37.2$ g $= 372 \times 1 0^{- 1}$ g.

$∴$ Required answer = 372.

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JEE Main 2025 Apr 2 Shift 1, Chemistry Q23: Mole Concept And Equivalent Concept

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