JEE Main 2025 Apr 4 Shift 1, Chemistry Q23: Mole Concept And Equivalent Concept

JEE Main2025Apr 4, Shift 1Chemistry

Fortification of food with iron is done using FeSO $_{4} \cdot$ 7H $_{2}$ O. The mass in grams of the FeSO $_{4} \cdot$ 7H $_{2}$ O required to achieve 12 ppm of iron in 150 kg of wheat is _____ (Nearest integer)

[Given : Molar mass of Fe, S and O respectively are 56, 32 and 16 g mol $^{- 1}$ ]

Your answer

Solution

12 ppm of Fe in 150 kg of wheat means mass of Fe required $= 12 \times 1 0^{- 6} \times (150 \times 1 0^{3}$ g $) = 1.8$ g.

Molar mass of FeSO $_{4} \cdot$ 7H $_{2}$ O $= 56 + 32 + 4 (16) + 7 (18) = 56 + 32 + 64 + 126 = 278$ g mol $^{- 1}$ .

Each mole of the salt provides 1 mole (56 g) of Fe, so the salt required is:

$m = 1.8 \times \frac{278}{56} \approx 8.93$ g.

Nearest integer = 9 g.

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JEE Main 2025 Apr 4 Shift 1, Chemistry Q23: Mole Concept And Equivalent Concept

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