JEE Main 2025 Jan 23 Shift 2, Chemistry Q21: Mole Concept And Equivalent Concept

JEE Main2025Jan 23, Shift 2Chemistry

0.01 mole of an organic compound (X) containing 10% hydrogen, on complete combustion produced 0.9 g H $_{2}$ O. Molar mass of (X) is ______ g mol $^{- 1}$ .

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Solution

Moles of H $_{2}$ O produced $= \frac{0.9}{18} = 0.05$ mol.

Each mole of H $_{2}$ O carries 2 mol of H atoms, so moles of H atoms generated $= 0.05 \times 2 = 0.10$ mol.

All this hydrogen came from 0.01 mol of X, giving $\frac{0.10}{0.01} = 10$ mol H per mole of X, i.e. $10$ g of H per mole of X.

The compound is 10% hydrogen by mass: $\frac{10}{M} \times 100 = 10 \Rightarrow M = 100$ g mol $^{- 1}$ .

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JEE Main 2025 Jan 23 Shift 2, Chemistry Q21: Mole Concept And Equivalent Concept

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