JEE Main 2026 — Apr 4, Shift 1 — Chemistry solution

JEE Main2026Apr 4, Shift 1Chemistry

Number of moles and number of molecules in $1.4187$ L of $S O_{2}$ at STP respectively are

Solution

At STP (as defined by IUPAC, $T = 273.15$ K, $P = 1$ bar), molar volume of an ideal gas is $22.7$ L mol $^{- 1}$ .

Moles $= \frac{V}{V _{m}} = \frac{1.4187}{22.7} \approx 0.0633$ mol.

Number of molecules $= n \times N_{A} = 0.0633 \times 6.022 \times 1 0^{23} \approx 3.812 \times 1 0^{22}$ .

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