JEE Main 2026 Apr 8 Shift 2, Chemistry Q1: Mole Concept And Equivalent Concept

JEE Main2026Apr 8, Shift 2Chemistry

Match List-I with List-II.

Choose the correct answer from the options given below :

Solution

For each sample compute moles, then multiply by the number of atoms per formula unit.

A. Water (H $_{2}$ O), $M = 18$ , atoms per molecule $= 3$ :

$\frac{1.8 \times 1 0 ^{- 3}}{18} \times 3 \times N_{A} = 3 \times 1 0^{- 4} N_{A}$ → III.

B. H $_{2}$ SO $_{4}$ , $M = 98$ , atoms per formula unit $= 7$ :

$\frac{9.8 \times 1 0 ^{- 3}}{98} \times 7 \times N_{A} = 7 \times 1 0^{- 4} N_{A}$ → IV.

C. Carbon, $M = 12$ , $1$ atom per formula unit:

$\frac{1.8 \times 1 0 ^{- 3}}{12} \times N_{A} = 1.5 \times 1 0^{- 4} N_{A}$ → II.

D. NaCl, $M = 58.5$ , $2$ atoms per formula unit:

$\frac{5.85 \times 1 0 ^{- 3}}{58.5} \times 2 \times N_{A} = 2 \times 1 0^{- 4} N_{A}$ → I.

$∴$ A-III, B-IV, C-II, D-I.

Concept behind this question

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