JEE Main 2026 — Jan 22, Shift 1 — Chemistry solution

JEE Main2026Jan 22, Shift 1Chemistry

In the reaction,

$2 A l (s) + 6 H C l (a q) \to 2 A l^{3 +} (a q) + 6 C l^{-} (a q) + 3 H_{2} (g)$

A
11.2 L $H_{2} (g)$ at STP is produced for every mole of HCl consumed.
B
67.2 L $H_{2} (g)$ at STP is produced for every mole of Al that reacts.
C
12 L HCl(aq) is consumed for every 6 L $H_{2} (g)$ produced.
D
33.6 L $H_{2} (g)$ is produced regardless of temperature and pressure for every mole of Al that reacts.

Solution

Read the stoichiometry: 6 mol HCl produces 3 mol $H_{2}$ , and 2 mol Al produces 3 mol $H_{2}$ .

Per mole of HCl: $\frac{3}{6} = 0.5$ mol $H_{2} = 0.5 \times 22.4 = 11.2$ L at STP. So (1) is correct.

Per mole of Al: $\frac{3}{2} = 1.5$ mol $H_{2} = 33.6$ L at STP — so (2) (67.2 L) is wrong, and (4) is wrong because the “regardless of T and P” qualifier is meaningless (the 33.6 L value is STP-specific).

Option (3) mixes solution volumes with gas volumes without specifying concentration, so it is not a determinate statement.

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