JEE Main 2026 — Apr 4, Shift 2 — Chemistry solution

JEE Main2026Apr 4, Shift 2Chemistry

The correct order of total number of atoms of present in

(A) 2 moles of cyclohexane

(B) 684 g of sucrose

A
C $>$ A $>$ B
B
C $>$ B $>$ A
C
B $>$ C $>$ A
D
B $>$ A $>$ C

Solution

(A) Cyclohexane is $C_{6} H_{12}$ , with 18 atoms per molecule. Total atoms $= 2 \times 18 N_{A} = 36 N_{A}$ .

(B) Sucrose ( $C_{12} H_{22} O_{11}$ ) has molar mass 342 g/mol and 45 atoms per molecule. Moles $= 684/342 = 2$ . Total atoms $= 2 \times 45 N_{A} = 90 N_{A}$ .

(C) At STP (modern: 22.7 L/mol), $n_{H_{2}} = 90.8/22.7 = 4$ mol. Total atoms $= 4 \times 2 N_{A} = 8 N_{A}$ .

$∴$ B $>$ A $>$ C.

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