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JEE Main 2025 Apr 3 Shift 1, Chemistry Q12: Diazonium Salt

JEE Main2025Apr 3, Shift 1Chemistry
Q.

Identify [A], [B], and [C], respectively in the following reaction sequence :

  1. A

    1

  2. B

    2

  3. C

    3

  4. D

    4

Solution

The reagent at 273–278 K is diazotisation, which converts a primary aromatic amine to an arenediazonium salt. So [A] must be aniline ().

Treatment of the diazonium salt with KI replaces the group by iodine (Sandmeyer-type substitution), giving iodobenzene as [B].

Iodobenzene with two equivalents of sodium in dry ether undergoes the Wurtz-Fittig (Fittig) coupling to form biphenyl (), which is [C].

[A] = aniline, [B] = iodobenzene, [C] = biphenyl.

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