JEE Main 2025 Apr 4 Shift 1, Physics Q1: Kinetic Theory of an Ideal Gases

JEE Main2025Apr 4, Shift 1Physics

The mean free path and the average speed of oxygen molecules at 300 K and 1 atm are $3 \times 1 0^{- 7}$ m and 600 m/s, respectively. Find the frequency of its collisions.

A
$2 \times 1 0^{10}$ /s
B
$9 \times 1 0^{5}$ /s
C
$2 \times 1 0^{9}$ /s
D
$5 \times 1 0^{8}$ /s

Solution

The collision frequency is the reciprocal of the mean free time, i.e. the average speed divided by the mean free path:

$ν = \frac{v _{avg}}{λ} = \frac{600}{3 \times 1 0 ^{- 7}} = 2 \times 1 0^{9} s^{- 1}$ .

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JEE Main 2025 Apr 4 Shift 1, Physics Q1: Kinetic Theory of an Ideal Gases

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