JEE Main 2025 Apr 4 Shift 1, Physics Q18: Coulomb's Law And Electric Field

JEE Main2025Apr 4, Shift 1Physics

Two infinite identical charged sheets and a charged spherical body of charge density ' $ρ$ ' are arranged as shown in figure. Then the correct relation between the electrical fields at A, B, C and D points is :

A
$∣ E_{A} ∣ = ∣ E_{B} ∣; E_{C} = E_{D}$
B
$∣ E_{A} ∣ > ∣ E_{B} ∣; E_{C} = E_{D}$
C
$E_{C} \neq = E_{D}; ∣ E_{A} ∣ > ∣ E_{B} ∣$
D
$∣ E_{A} ∣ = ∣ E_{B} ∣; E_{C} > E_{D}$

Solution

The infinite sheets contribute a uniform field whose magnitude is the same everywhere outside them; the only spatial variation comes from the central charged sphere.

At A (closer to the sphere) the field of the sphere is stronger than at B (farther from it), and the contributions of the sheet fields at A and B are identical. So $∣ E_{A} ∣ > ∣ E_{B} ∣$ .

At C (far outside the sheets on the left) the sphere's field still contributes, but it is not symmetric: C and D are on opposite sides of the sphere, so the sphere's field has opposite directions at the two points while the sheet contribution is uniform. The net fields therefore differ: $E_{C} \neq = E_{D}$ .

$∴$ Option (3) is correct.

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JEE Main 2025 Apr 4 Shift 1, Physics Q18: Coulomb's Law And Electric Field

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