JEE Main 2025 Apr 4 Shift 2, Physics Q11: Motion In One Dimension

JEE Main2025Apr 4, Shift 2Physics

The displacement $x$ versus time graph is shown below.

(A) The average velocity during 0 to 3 s is 10 m/s

(B) The average velocity during 3 to 5 s is 0 m/s

(D) The average velocity during 5 to 7 s and instantaneous velocity at $t = 6.5$ s are equal

(E) The average velocity from $t = 0$ to $t = 9$ s is zero

Choose the correct answer from the options given below:

Solution

$\langle\vec{v}\rangle=\dfrac{\Delta\vec{s}}{\Delta t} =\dfrac{S_f-S_i}{t_f-t_i}$

$v = \frac{d s}{d t} = slope$

(A) $0$ to $3 s$ :

$⟨ v ⟩ = \frac{5 - 0}{3 - 0} = \frac{5}{3} m s^{- 1}$

(B) $0$ to $5 s$ :

$⟨ v ⟩ = \frac{5 - 5}{5 - 0} = 0$

(C) At $t = 2 s$ :

$v = slope = 5 m s^{- 1}$

(D) $5$ to $7 s$ :

$⟨ v ⟩ = \frac{0 - 5}{7 - 5} = - 2.5 m s^{- 1}$

At $t = 6.5 s$ , $v = 10 m s^{- 1}$

(E) $0$ to $9 s$ :

$⟨ v ⟩ = \frac{0 - 0}{9 - 0} = 0$

Concept behind this question

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