JEE Main 2025 Apr 4 Shift 2, Physics Q17: Thermodynamic Processes

JEE Main2025Apr 4, Shift 2Physics

Match List-I with List-II.

	List-I		List-II
(A)	Isobaric	(I)	$Δ Q = Δ W$
(B)	Isochoric	(II)	$Δ Q = Δ U$
(C)	Adiabatic	(III)	$Δ Q =$ zero
(D)	Isothermal	(IV)	$Δ Q = Δ U + P Δ V$

$Δ Q$ = Heat supplied; $Δ W$ = Work done by the system; $Δ U$ = Change in internal energy; $P$ = Pressure of the system; $Δ V$ = Change in volume of the system.

Choose the correct answer from the options given below :

A
(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
B
(A)-(IV), (B)-(I), (C)-(III), (D)-(II)
C
(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
D
(A)-(II), (B)-(IV), (C)-(III), (D)-(I)

Solution

Apply the first law $Δ Q = Δ U + Δ W$ to each constraint.

(A) Isobaric ( $P$ constant): $Δ W = P Δ V$ , so $Δ Q = Δ U + P Δ V$ — matches (IV).

(B) Isochoric ( $V$ constant): $Δ W = 0$ , so $Δ Q = Δ U$ — matches (II).

(C) Adiabatic: no heat exchange, so $Δ Q = 0$ — matches (III).

(D) Isothermal ( $T$ constant, ideal gas $\Rightarrow Δ U = 0$ ): so $Δ Q = Δ W$ — matches (I).

$∴$ A-IV, B-II, C-III, D-I.

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JEE Main 2025 Apr 4 Shift 2, Physics Q17: Thermodynamic Processes

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