JEE Main 2025 Apr 8 Shift 2, Physics Q8: Semiconductors, p-n Junction Diode and Applications

The resistor pulls the output node towards +5 V.

Initially, assume $V_{\text{out}}=+5\text{ V}$.

Diode $D_1$: Both terminals are at $+5\text{ V}$, so it is not forward biased.

Diode $D_2$: As $V_{\text{out}}$ tends to become greater than $0\text{ V}$, $D_2$ becomes forward biased (ideal diode) and clamps the output to ground.

$\therefore \boxed{V_{\text{out}}=0\text{ V}}$