JEE Main 2025 Jan 22 Shift 2, Physics Q17: Interference by Thin Film
JEE Main2025Jan 22, Shift 2Physics
Q.
A transparent film of refractive index, 2.0 is coated on a glass slab of refractive index, 1.45. What is the minimum thickness of transparent film to be coated for the maximum transmission of Green light of wavelength 550 nm. [Assume that the light is incident nearly perpendicular to the glass surface.]
- A
94.8 nm
- B
68.7 nm
- C
137.5 nm
- D
275 nm
Solution
$ \text{For transmitted green light to be maximum, reflected green light should be minimum.} $
$ \Delta P=2\mu_0t=n\lambda $
$ \Rightarrow t=\dfrac{n\lambda}{2\mu_0} $
$ \therefore t_{\min} =\dfrac{\lambda}{2\mu_0} =\dfrac{550}{2\times2} =137.5\ \text{nm} $
Concept behind this question
Interference by Thin FilmNotes, formulas and examples →More previous year questions on Interference by Thin Film
Practice more Physics
Concept-wise practice with instant solutions on Fundamenthol.
Start practicing →