JEE Main 2025 Jan 23 Shift 1, Physics Q23: Thermodynamic Processes

JEE Main2025Jan 23, Shift 1Physics

An ideal gas initially at $0^{\circ}$ C temperature, is compressed suddenly to one fourth of its volume. If the ratio of specific heat at constant pressure to that at constant volume is 3/2, the change in temperature due to the thermodynamics process is ____ K.

Your answer

Solution

'Sudden' compression is adiabatic. For an ideal gas, $T V^{γ - 1} = const$ . With $γ = 3/2$ , $γ - 1 = 1/2$ .

$T_{1} V_{1}^{1/2} = T_{2} V_{2}^{1/2}$ and $V_{2} = V_{1} /4$ :

$T_{2} = T_{1} (\frac{V _{1}}{V _{2}})^{1/2} = 273 \times 4 = 546$ K.

$Δ T = 546 - 273 = 273$ K.

Concept behind this question

Thermodynamic ProcessesNotes, formulas and examples →

Practice more Physics

Concept-wise practice with instant solutions on Fundamenthol.

Start practicing →

JEE Main 2025 Jan 23 Shift 1, Physics Q23: Thermodynamic Processes

Concept behind this question

More previous year questions on Thermodynamic Processes

Practice more Physics