JEE Main 2025 Jan 24 Shift 2, Chemistry Q25: Qualitative and Quantitative Analysis

JEE Main2025Jan 24, Shift 2Chemistry

In Carius method of estimation of halogen, 0.25 g of an organic compound gave 0.15 g of silver bromide (AgBr). The percentage of Bromine in the organic compound is ____________ $\times 1 0^{- 1} %$ (Nearest integer).

(Given : Molar mass of Ag is 108 and Br is 80 g mol $^{- 1}$ )

Your answer

Solution

In the Carius method, all the bromine in the organic sample is precipitated as AgBr. The percentage of Br is obtained from:

$% B r = \frac{M _{B r}}{M _{A g B r}} \times \frac{mass of AgBr}{mass of sample} \times 100$

$M_{A g B r} = 108 + 80 = 188 g mol^{- 1}$ .

$% B r = \frac{80}{188} \times \frac{0.15}{0.25} \times 100 \approx 25.5% \approx 255 \times 1 0^{- 1}$

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JEE Main 2025 Jan 24 Shift 2, Chemistry Q25: Qualitative and Quantitative Analysis

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