JEE Main 2025 Jan 29 Shift 1, Chemistry Q24: Abnormal Molar Masses

JEE Main2025Jan 29, Shift 1Chemistry

If $A_{2} B$ is 30% ionised in an aqueous solution, then the value of van't Hoff factor ( $i$ ) is _____ $\times 1 0^{- 1}$ .

Your answer

Solution

Dissociation: $A_{2} B \to 2 A^{+} + B^{2 -}$ , so the number of particles per formula unit is $y = 3$ , and the given degree of ionisation is $α = 0.30$ .

Van't Hoff factor: $i = 1 + (y - 1) α = 1 + 2 (0.30) = 1.60.$

Expressed as $\times 1 0^{- 1}$ : $i = 16 \times 1 0^{- 1} .$

Concept behind this question

Abnormal Molar MassesNotes, formulas and examples →

Practice more Chemistry

Concept-wise practice with instant solutions on Fundamenthol.

Start practicing →

JEE Main 2025 Jan 29 Shift 1, Chemistry Q24: Abnormal Molar Masses

Concept behind this question

More previous year questions on Abnormal Molar Masses

Practice more Chemistry